mysql запрос

SELECT `user_id`, `editor`, `news_read` FROM `имя таблицы`

SELECT COUNT(`news_id `) as `news_count`, SUM(`news_read`) as `read_count`, `user_id` FROM `table` WHERE `editor` = 'ololo'

    $q = mysql_query("SELECT `user_id`, `news_read`, `editor` FROM `table`");
    $data = array();
    
    while($data = mysql_fetch_array($q)){
        $data[] = $q;
    }
    
    for($i=0; $i<count($data); $i++){
        for($j=0; $j<count($data); $j++){
            $data[$i]['news_sum'] = $data[$i]['news_read'];
            if($data[$i]['editor'] == $data[$j]['editor']){
                $data[$i]['news_sum'] = $data[$i]['news_sum'] + $data[$j]['news_read'];
                unset($data[$j]);
            }
        }
    }

$connect = mysql_query("SELECT `id`, `editor`, `news_read` FROM `ТВОЯ БД`");

while($user = mysql_fetch_object($connect))
{
          echo $user->id;
          echo "<br/><b>". $user->editor ."</b>";
}